What angle will the superior blade of a windmill be from vertical after 35 seconds if it accelerates at 4.38 rad/s²?

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To determine the angle of the superior blade of the windmill after 35 seconds of acceleration at 4.38 rad/s², one can use the equation for angular displacement under constant angular acceleration. The formula to calculate the angular displacement (θ) in radians is:

θ = ω₀t + (1/2)αt²

where

  • ω₀ is the initial angular velocity (which is assumed to be 0 if not provided),

  • α is the angular acceleration,

  • t is the time in seconds.

Given:

  • Initial angular velocity (ω₀) = 0 rad/s

  • Angular acceleration (α) = 4.38 rad/s²

  • Time (t) = 35 seconds

Substituting these values into the equation:

θ = 0 × 35 + (1/2) × 4.38 × (35)²

θ = 0 + (1/2) × 4.38 × 1225

θ = 2.19 × 1225

θ ≈ 2687.75 rad

However, since this value appears unreasonably high for a simple angular motion scenario, it's important to recognize that angular displacements

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