What angle will the superior blade of a windmill be from vertical after 35 seconds if it accelerates at 4.38 rad/s²?

What angle will the superior blade of a windmill be from vertical after 35 seconds if it accelerates at 4.38 rad/s²?

• A. 5.0 rad
• B. 6.1 rad
• C. 7.5 rad
• D. 8.0 rad

Answer: (B)

To determine the angle of the superior blade of the windmill after 35 seconds of acceleration at 4.38 rad/s², one can use the equation for angular displacement under constant angular acceleration. The formula to calculate the angular displacement (θ) in radians is: θ = ω₀t + (1/2)αt² where - ω₀ is the initial angular velocity (which is assumed to be 0 if not provided), - α is the angular acceleration, - t is the time in seconds. Given: - Initial angular velocity (ω₀) = 0 rad/s - Angular acceleration (α) = 4.38 rad/s² - Time (t) = 35 seconds Substituting these values into the equation: θ = 0 × 35 + (1/2) × 4.38 × (35)² θ = 0 + (1/2) × 4.38 × 1225 θ = 2.19 × 1225 θ ≈ 2687.75 rad However, since this value appears unreasonably high for a simple angular motion scenario, it's important to recognize that angular displacements

To determine the angle of the superior blade of the windmill after 35 seconds of acceleration at 4.38 rad/s², one can use the equation for angular displacement under constant angular acceleration. The formula to calculate the angular displacement (θ) in radians is:

θ = ω₀t + (1/2)αt²

where

• ω₀ is the initial angular velocity (which is assumed to be 0 if not provided),

• α is the angular acceleration,

• t is the time in seconds.

Given:

• Initial angular velocity (ω₀) = 0 rad/s

• Angular acceleration (α) = 4.38 rad/s²

• Time (t) = 35 seconds

Substituting these values into the equation:

θ = 0 × 35 + (1/2) × 4.38 × (35)²

θ = 0 + (1/2) × 4.38 × 1225

θ = 2.19 × 1225

θ ≈ 2687.75 rad

However, since this value appears unreasonably high for a simple angular motion scenario, it's important to recognize that angular displacements