What is the magnitude of torque produced by a force of 2.4 N applied at a distance of 17 cm from the point of rotation at an angle of 45 degrees?

To determine the magnitude of torque produced by a force, the formula used is:

Torque (τ) = r * F * sin(θ)

where:

• r is the distance from the point of rotation to the point where the force is applied (in meters),

• F is the magnitude of the applied force (in Newtons), and

• θ is the angle between the force vector and the line from the point of rotation to the point of application of the force.

In this case:

• The distance r is given as 17 cm, which converts to meters by dividing by 100, resulting in 0.17 m.

• The force F is 2.4 N.

• The angle θ is given as 45 degrees.

Now, applying the values to the formula:

1. Calculate sin(θ):

sin(45 degrees) = √2 / 2 (approximately 0.7071).

2. Substitute the values into the torque formula:

τ = 0.17 m * 2.4 N * 0.7071.

3. Conduct the multiplication:

τ ≈ 0.17 * 2.4 * 0.7071 = 0.17 * 1