What occurrence will happen to an hourglass-shaped object when it is free to rotate?

An hourglass-shaped object, when free to rotate, will not exhibit any movement on its own unless acted upon by an external force. This is due to the principles of equilibrium and inertia. If the object is balanced and there are no external forces acting on it, such as gravitational pull or a force from the surface it rests on, it will remain in its initial state and will not move. The shape of the hourglass itself does not inherently cause it to tip over or spin; any movement would require a push or pull that disrupts its equilibrium.

In contrast, options that suggest movement (spinning, upward motion, or falling over) would imply the presence of an external influence, which is not accounted for in the scenario presented. Thus, in the absence of such influences, the correct understanding is that the object remains stationary.